3.38 \(\int \frac {1}{(b x+c x^2)^{4/3}} \, dx\)

Optimal. Leaf size=773 \[ \frac {3 (b+2 c x) \left (-\frac {c \left (b x+c x^2\right )}{b^2}\right )^{4/3}}{c \sqrt [3]{-\frac {c x (b+c x)}{b^2}} \left (b x+c x^2\right )^{4/3}}+\frac {3\ 2^{2/3} (b+2 c x) \left (-\frac {c \left (b x+c x^2\right )}{b^2}\right )^{4/3}}{c \left (b x+c x^2\right )^{4/3} \left (-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}-\sqrt {3}+1\right )}-\frac {2 \sqrt [6]{2} 3^{3/4} b^2 \left (-\frac {c \left (b x+c x^2\right )}{b^2}\right )^{4/3} \left (1-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}\right ) \sqrt {\frac {2 \sqrt [3]{2} \left (-\frac {c x (b+c x)}{b^2}\right )^{2/3}+2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}+1}{\left (-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}-\sqrt {3}+1\right )^2}} F\left (\sin ^{-1}\left (\frac {-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}+\sqrt {3}+1}{-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}-\sqrt {3}+1}\right )|-7+4 \sqrt {3}\right )}{c (b+2 c x) \left (b x+c x^2\right )^{4/3} \sqrt {-\frac {1-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}}{\left (-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}-\sqrt {3}+1\right )^2}}}+\frac {3 \sqrt [4]{3} \sqrt {2+\sqrt {3}} b^2 \left (-\frac {c \left (b x+c x^2\right )}{b^2}\right )^{4/3} \left (1-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}\right ) \sqrt {\frac {2 \sqrt [3]{2} \left (-\frac {c x (b+c x)}{b^2}\right )^{2/3}+2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}+1}{\left (-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}-\sqrt {3}+1\right )^2}} E\left (\sin ^{-1}\left (\frac {-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}+\sqrt {3}+1}{-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}-\sqrt {3}+1}\right )|-7+4 \sqrt {3}\right )}{\sqrt [3]{2} c (b+2 c x) \left (b x+c x^2\right )^{4/3} \sqrt {-\frac {1-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}}{\left (-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}-\sqrt {3}+1\right )^2}}} \]

[Out]

3*(2*c*x+b)*(-c*(c*x^2+b*x)/b^2)^(4/3)/c/(-c*x*(c*x+b)/b^2)^(1/3)/(c*x^2+b*x)^(4/3)+3*2^(2/3)*(2*c*x+b)*(-c*(c
*x^2+b*x)/b^2)^(4/3)/c/(c*x^2+b*x)^(4/3)/(1-2^(2/3)*(-c*x*(c*x+b)/b^2)^(1/3)-3^(1/2))-2*2^(1/6)*3^(3/4)*b^2*(-
c*(c*x^2+b*x)/b^2)^(4/3)*(1-2^(2/3)*(-c*x*(c*x+b)/b^2)^(1/3))*EllipticF((1-2^(2/3)*(-c*x*(c*x+b)/b^2)^(1/3)+3^
(1/2))/(1-2^(2/3)*(-c*x*(c*x+b)/b^2)^(1/3)-3^(1/2)),2*I-I*3^(1/2))*((1+2^(2/3)*(-c*x*(c*x+b)/b^2)^(1/3)+2*2^(1
/3)*(-c*x*(c*x+b)/b^2)^(2/3))/(1-2^(2/3)*(-c*x*(c*x+b)/b^2)^(1/3)-3^(1/2))^2)^(1/2)/c/(2*c*x+b)/(c*x^2+b*x)^(4
/3)/((-1+2^(2/3)*(-c*x*(c*x+b)/b^2)^(1/3))/(1-2^(2/3)*(-c*x*(c*x+b)/b^2)^(1/3)-3^(1/2))^2)^(1/2)+3/2*3^(1/4)*b
^2*(-c*(c*x^2+b*x)/b^2)^(4/3)*(1-2^(2/3)*(-c*x*(c*x+b)/b^2)^(1/3))*EllipticE((1-2^(2/3)*(-c*x*(c*x+b)/b^2)^(1/
3)+3^(1/2))/(1-2^(2/3)*(-c*x*(c*x+b)/b^2)^(1/3)-3^(1/2)),2*I-I*3^(1/2))*((1+2^(2/3)*(-c*x*(c*x+b)/b^2)^(1/3)+2
*2^(1/3)*(-c*x*(c*x+b)/b^2)^(2/3))/(1-2^(2/3)*(-c*x*(c*x+b)/b^2)^(1/3)-3^(1/2))^2)^(1/2)*(1/2*6^(1/2)+1/2*2^(1
/2))*2^(2/3)/c/(2*c*x+b)/(c*x^2+b*x)^(4/3)/((-1+2^(2/3)*(-c*x*(c*x+b)/b^2)^(1/3))/(1-2^(2/3)*(-c*x*(c*x+b)/b^2
)^(1/3)-3^(1/2))^2)^(1/2)

________________________________________________________________________________________

Rubi [A]  time = 0.95, antiderivative size = 773, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 7, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.538, Rules used = {622, 619, 199, 235, 304, 219, 1879} \[ \frac {3 (b+2 c x) \left (-\frac {c \left (b x+c x^2\right )}{b^2}\right )^{4/3}}{c \sqrt [3]{-\frac {c x (b+c x)}{b^2}} \left (b x+c x^2\right )^{4/3}}+\frac {3\ 2^{2/3} (b+2 c x) \left (-\frac {c \left (b x+c x^2\right )}{b^2}\right )^{4/3}}{c \left (b x+c x^2\right )^{4/3} \left (-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}-\sqrt {3}+1\right )}-\frac {2 \sqrt [6]{2} 3^{3/4} b^2 \left (-\frac {c \left (b x+c x^2\right )}{b^2}\right )^{4/3} \left (1-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}\right ) \sqrt {\frac {2 \sqrt [3]{2} \left (-\frac {c x (b+c x)}{b^2}\right )^{2/3}+2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}+1}{\left (-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}-\sqrt {3}+1\right )^2}} F\left (\sin ^{-1}\left (\frac {-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}+\sqrt {3}+1}{-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}-\sqrt {3}+1}\right )|-7+4 \sqrt {3}\right )}{c (b+2 c x) \left (b x+c x^2\right )^{4/3} \sqrt {-\frac {1-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}}{\left (-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}-\sqrt {3}+1\right )^2}}}+\frac {3 \sqrt [4]{3} \sqrt {2+\sqrt {3}} b^2 \left (-\frac {c \left (b x+c x^2\right )}{b^2}\right )^{4/3} \left (1-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}\right ) \sqrt {\frac {2 \sqrt [3]{2} \left (-\frac {c x (b+c x)}{b^2}\right )^{2/3}+2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}+1}{\left (-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}-\sqrt {3}+1\right )^2}} E\left (\sin ^{-1}\left (\frac {-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}+\sqrt {3}+1}{-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}-\sqrt {3}+1}\right )|-7+4 \sqrt {3}\right )}{\sqrt [3]{2} c (b+2 c x) \left (b x+c x^2\right )^{4/3} \sqrt {-\frac {1-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}}{\left (-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}-\sqrt {3}+1\right )^2}}} \]

Antiderivative was successfully verified.

[In]

Int[(b*x + c*x^2)^(-4/3),x]

[Out]

(3*(b + 2*c*x)*(-((c*(b*x + c*x^2))/b^2))^(4/3))/(c*(-((c*x*(b + c*x))/b^2))^(1/3)*(b*x + c*x^2)^(4/3)) + (3*2
^(2/3)*(b + 2*c*x)*(-((c*(b*x + c*x^2))/b^2))^(4/3))/(c*(b*x + c*x^2)^(4/3)*(1 - Sqrt[3] - 2^(2/3)*(-((c*x*(b
+ c*x))/b^2))^(1/3))) + (3*3^(1/4)*Sqrt[2 + Sqrt[3]]*b^2*(-((c*(b*x + c*x^2))/b^2))^(4/3)*(1 - 2^(2/3)*(-((c*x
*(b + c*x))/b^2))^(1/3))*Sqrt[(1 + 2^(2/3)*(-((c*x*(b + c*x))/b^2))^(1/3) + 2*2^(1/3)*(-((c*x*(b + c*x))/b^2))
^(2/3))/(1 - Sqrt[3] - 2^(2/3)*(-((c*x*(b + c*x))/b^2))^(1/3))^2]*EllipticE[ArcSin[(1 + Sqrt[3] - 2^(2/3)*(-((
c*x*(b + c*x))/b^2))^(1/3))/(1 - Sqrt[3] - 2^(2/3)*(-((c*x*(b + c*x))/b^2))^(1/3))], -7 + 4*Sqrt[3]])/(2^(1/3)
*c*(b + 2*c*x)*(b*x + c*x^2)^(4/3)*Sqrt[-((1 - 2^(2/3)*(-((c*x*(b + c*x))/b^2))^(1/3))/(1 - Sqrt[3] - 2^(2/3)*
(-((c*x*(b + c*x))/b^2))^(1/3))^2)]) - (2*2^(1/6)*3^(3/4)*b^2*(-((c*(b*x + c*x^2))/b^2))^(4/3)*(1 - 2^(2/3)*(-
((c*x*(b + c*x))/b^2))^(1/3))*Sqrt[(1 + 2^(2/3)*(-((c*x*(b + c*x))/b^2))^(1/3) + 2*2^(1/3)*(-((c*x*(b + c*x))/
b^2))^(2/3))/(1 - Sqrt[3] - 2^(2/3)*(-((c*x*(b + c*x))/b^2))^(1/3))^2]*EllipticF[ArcSin[(1 + Sqrt[3] - 2^(2/3)
*(-((c*x*(b + c*x))/b^2))^(1/3))/(1 - Sqrt[3] - 2^(2/3)*(-((c*x*(b + c*x))/b^2))^(1/3))], -7 + 4*Sqrt[3]])/(c*
(b + 2*c*x)*(b*x + c*x^2)^(4/3)*Sqrt[-((1 - 2^(2/3)*(-((c*x*(b + c*x))/b^2))^(1/3))/(1 - Sqrt[3] - 2^(2/3)*(-(
(c*x*(b + c*x))/b^2))^(1/3))^2)])

Rule 199

Int[((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> -Simp[(x*(a + b*x^n)^(p + 1))/(a*n*(p + 1)), x] + Dist[(n*(p +
1) + 1)/(a*n*(p + 1)), Int[(a + b*x^n)^(p + 1), x], x] /; FreeQ[{a, b}, x] && IGtQ[n, 0] && LtQ[p, -1] && (In
tegerQ[2*p] || (n == 2 && IntegerQ[4*p]) || (n == 2 && IntegerQ[3*p]) || Denominator[p + 1/n] < Denominator[p]
)

Rule 219

Int[1/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = Numer[Rt[b/a, 3]], s = Denom[Rt[b/a, 3]]}, Simp[(2*Sqr
t[2 - Sqrt[3]]*(s + r*x)*Sqrt[(s^2 - r*s*x + r^2*x^2)/((1 - Sqrt[3])*s + r*x)^2]*EllipticF[ArcSin[((1 + Sqrt[3
])*s + r*x)/((1 - Sqrt[3])*s + r*x)], -7 + 4*Sqrt[3]])/(3^(1/4)*r*Sqrt[a + b*x^3]*Sqrt[-((s*(s + r*x))/((1 - S
qrt[3])*s + r*x)^2)]), x]] /; FreeQ[{a, b}, x] && NegQ[a]

Rule 235

Int[((a_) + (b_.)*(x_)^2)^(-1/3), x_Symbol] :> Dist[(3*Sqrt[b*x^2])/(2*b*x), Subst[Int[x/Sqrt[-a + x^3], x], x
, (a + b*x^2)^(1/3)], x] /; FreeQ[{a, b}, x]

Rule 304

Int[(x_)/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = Numer[Rt[b/a, 3]], s = Denom[Rt[b/a, 3]]}, -Dist[(S
qrt[2]*s)/(Sqrt[2 - Sqrt[3]]*r), Int[1/Sqrt[a + b*x^3], x], x] + Dist[1/r, Int[((1 + Sqrt[3])*s + r*x)/Sqrt[a
+ b*x^3], x], x]] /; FreeQ[{a, b}, x] && NegQ[a]

Rule 619

Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Dist[1/(2*c*((-4*c)/(b^2 - 4*a*c))^p), Subst[Int[Si
mp[1 - x^2/(b^2 - 4*a*c), x]^p, x], x, b + 2*c*x], x] /; FreeQ[{a, b, c, p}, x] && GtQ[4*a - b^2/c, 0]

Rule 622

Int[((b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Dist[(b*x + c*x^2)^p/(-((c*(b*x + c*x^2))/b^2))^p, Int[(-((
c*x)/b) - (c^2*x^2)/b^2)^p, x], x] /; FreeQ[{b, c}, x] && RationalQ[p] && 3 <= Denominator[p] <= 4

Rule 1879

Int[((c_) + (d_.)*(x_))/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = Numer[Simplify[((1 + Sqrt[3])*d)/c]]
, s = Denom[Simplify[((1 + Sqrt[3])*d)/c]]}, Simp[(2*d*s^3*Sqrt[a + b*x^3])/(a*r^2*((1 - Sqrt[3])*s + r*x)), x
] + Simp[(3^(1/4)*Sqrt[2 + Sqrt[3]]*d*s*(s + r*x)*Sqrt[(s^2 - r*s*x + r^2*x^2)/((1 - Sqrt[3])*s + r*x)^2]*Elli
pticE[ArcSin[((1 + Sqrt[3])*s + r*x)/((1 - Sqrt[3])*s + r*x)], -7 + 4*Sqrt[3]])/(r^2*Sqrt[a + b*x^3]*Sqrt[-((s
*(s + r*x))/((1 - Sqrt[3])*s + r*x)^2)]), x]] /; FreeQ[{a, b, c, d}, x] && NegQ[a] && EqQ[b*c^3 - 2*(5 + 3*Sqr
t[3])*a*d^3, 0]

Rubi steps

\begin {align*} \int \frac {1}{\left (b x+c x^2\right )^{4/3}} \, dx &=\frac {\left (-\frac {c \left (b x+c x^2\right )}{b^2}\right )^{4/3} \int \frac {1}{\left (-\frac {c x}{b}-\frac {c^2 x^2}{b^2}\right )^{4/3}} \, dx}{\left (b x+c x^2\right )^{4/3}}\\ &=-\frac {\left (2\ 2^{2/3} b^2 \left (-\frac {c \left (b x+c x^2\right )}{b^2}\right )^{4/3}\right ) \operatorname {Subst}\left (\int \frac {1}{\left (1-\frac {b^2 x^2}{c^2}\right )^{4/3}} \, dx,x,-\frac {c}{b}-\frac {2 c^2 x}{b^2}\right )}{c^2 \left (b x+c x^2\right )^{4/3}}\\ &=\frac {3 (b+2 c x) \left (-\frac {c \left (b x+c x^2\right )}{b^2}\right )^{4/3}}{c \sqrt [3]{-\frac {c x (b+c x)}{b^2}} \left (b x+c x^2\right )^{4/3}}+\frac {\left (2^{2/3} b^2 \left (-\frac {c \left (b x+c x^2\right )}{b^2}\right )^{4/3}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt [3]{1-\frac {b^2 x^2}{c^2}}} \, dx,x,-\frac {c}{b}-\frac {2 c^2 x}{b^2}\right )}{c^2 \left (b x+c x^2\right )^{4/3}}\\ &=\frac {3 (b+2 c x) \left (-\frac {c \left (b x+c x^2\right )}{b^2}\right )^{4/3}}{c \sqrt [3]{-\frac {c x (b+c x)}{b^2}} \left (b x+c x^2\right )^{4/3}}-\frac {\left (3 \left (-\frac {c \left (b x+c x^2\right )}{b^2}\right )^{4/3} \sqrt {-1-\frac {4 c x}{b}-\frac {4 c^2 x^2}{b^2}}\right ) \operatorname {Subst}\left (\int \frac {x}{\sqrt {-1+x^3}} \, dx,x,2^{2/3} \sqrt [3]{-\frac {c x \left (1+\frac {c x}{b}\right )}{b}}\right )}{\sqrt [3]{2} \left (-\frac {c}{b}-\frac {2 c^2 x}{b^2}\right ) \left (b x+c x^2\right )^{4/3}}\\ &=\frac {3 (b+2 c x) \left (-\frac {c \left (b x+c x^2\right )}{b^2}\right )^{4/3}}{c \sqrt [3]{-\frac {c x (b+c x)}{b^2}} \left (b x+c x^2\right )^{4/3}}+\frac {\left (3 \left (-\frac {c \left (b x+c x^2\right )}{b^2}\right )^{4/3} \sqrt {-1-\frac {4 c x}{b}-\frac {4 c^2 x^2}{b^2}}\right ) \operatorname {Subst}\left (\int \frac {1+\sqrt {3}-x}{\sqrt {-1+x^3}} \, dx,x,2^{2/3} \sqrt [3]{-\frac {c x \left (1+\frac {c x}{b}\right )}{b}}\right )}{\sqrt [3]{2} \left (-\frac {c}{b}-\frac {2 c^2 x}{b^2}\right ) \left (b x+c x^2\right )^{4/3}}-\frac {\left (3 \sqrt [6]{2} \sqrt {2+\sqrt {3}} \left (-\frac {c \left (b x+c x^2\right )}{b^2}\right )^{4/3} \sqrt {-1-\frac {4 c x}{b}-\frac {4 c^2 x^2}{b^2}}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {-1+x^3}} \, dx,x,2^{2/3} \sqrt [3]{-\frac {c x \left (1+\frac {c x}{b}\right )}{b}}\right )}{\left (-\frac {c}{b}-\frac {2 c^2 x}{b^2}\right ) \left (b x+c x^2\right )^{4/3}}\\ &=\frac {3 (b+2 c x) \left (-\frac {c \left (b x+c x^2\right )}{b^2}\right )^{4/3}}{c \sqrt [3]{-\frac {c x (b+c x)}{b^2}} \left (b x+c x^2\right )^{4/3}}-\frac {3\ 2^{2/3} b^2 \left (-\frac {c \left (b x+c x^2\right )}{b^2}\right )^{4/3} \sqrt {-1-\frac {4 c x}{b}-\frac {4 c^2 x^2}{b^2}} \sqrt {-1-\frac {4 c x (b+c x)}{b^2}}}{c (b+2 c x) \left (b x+c x^2\right )^{4/3} \left (1-\sqrt {3}-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}\right )}+\frac {3 \sqrt [4]{3} \sqrt {2+\sqrt {3}} b^2 \left (-\frac {c \left (b x+c x^2\right )}{b^2}\right )^{4/3} \sqrt {-1-\frac {4 c x}{b}-\frac {4 c^2 x^2}{b^2}} \left (1-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}\right ) \sqrt {\frac {1+2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}+2 \sqrt [3]{2} \left (-\frac {c x (b+c x)}{b^2}\right )^{2/3}}{\left (1-\sqrt {3}-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}\right )^2}} E\left (\sin ^{-1}\left (\frac {1+\sqrt {3}-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}}{1-\sqrt {3}-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}}\right )|-7+4 \sqrt {3}\right )}{\sqrt [3]{2} c (b+2 c x) \left (b x+c x^2\right )^{4/3} \sqrt {-1-\frac {4 c x (b+c x)}{b^2}} \sqrt {-\frac {1-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}}{\left (1-\sqrt {3}-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}\right )^2}}}-\frac {2 \sqrt [6]{2} 3^{3/4} b^2 \left (-\frac {c \left (b x+c x^2\right )}{b^2}\right )^{4/3} \sqrt {-1-\frac {4 c x}{b}-\frac {4 c^2 x^2}{b^2}} \left (1-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}\right ) \sqrt {\frac {1+2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}+2 \sqrt [3]{2} \left (-\frac {c x (b+c x)}{b^2}\right )^{2/3}}{\left (1-\sqrt {3}-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}\right )^2}} F\left (\sin ^{-1}\left (\frac {1+\sqrt {3}-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}}{1-\sqrt {3}-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}}\right )|-7+4 \sqrt {3}\right )}{c (b+2 c x) \left (b x+c x^2\right )^{4/3} \sqrt {-1-\frac {4 c x (b+c x)}{b^2}} \sqrt {-\frac {1-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}}{\left (1-\sqrt {3}-2^{2/3} \sqrt [3]{-\frac {c x (b+c x)}{b^2}}\right )^2}}}\\ \end {align*}

________________________________________________________________________________________

Mathematica [C]  time = 0.01, size = 45, normalized size = 0.06 \[ -\frac {3 \sqrt [3]{\frac {c x}{b}+1} \, _2F_1\left (-\frac {1}{3},\frac {4}{3};\frac {2}{3};-\frac {c x}{b}\right )}{b \sqrt [3]{x (b+c x)}} \]

Antiderivative was successfully verified.

[In]

Integrate[(b*x + c*x^2)^(-4/3),x]

[Out]

(-3*(1 + (c*x)/b)^(1/3)*Hypergeometric2F1[-1/3, 4/3, 2/3, -((c*x)/b)])/(b*(x*(b + c*x))^(1/3))

________________________________________________________________________________________

fricas [F]  time = 0.97, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {{\left (c x^{2} + b x\right )}^{\frac {2}{3}}}{c^{2} x^{4} + 2 \, b c x^{3} + b^{2} x^{2}}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(c*x^2+b*x)^(4/3),x, algorithm="fricas")

[Out]

integral((c*x^2 + b*x)^(2/3)/(c^2*x^4 + 2*b*c*x^3 + b^2*x^2), x)

________________________________________________________________________________________

giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{{\left (c x^{2} + b x\right )}^{\frac {4}{3}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(c*x^2+b*x)^(4/3),x, algorithm="giac")

[Out]

integrate((c*x^2 + b*x)^(-4/3), x)

________________________________________________________________________________________

maple [F]  time = 0.88, size = 0, normalized size = 0.00 \[ \int \frac {1}{\left (c \,x^{2}+b x \right )^{\frac {4}{3}}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(c*x^2+b*x)^(4/3),x)

[Out]

int(1/(c*x^2+b*x)^(4/3),x)

________________________________________________________________________________________

maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{{\left (c x^{2} + b x\right )}^{\frac {4}{3}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(c*x^2+b*x)^(4/3),x, algorithm="maxima")

[Out]

integrate((c*x^2 + b*x)^(-4/3), x)

________________________________________________________________________________________

mupad [B]  time = 0.23, size = 36, normalized size = 0.05 \[ -\frac {3\,x\,{\left (\frac {c\,x}{b}+1\right )}^{4/3}\,{{}}_2{\mathrm {F}}_1\left (-\frac {1}{3},\frac {4}{3};\ \frac {2}{3};\ -\frac {c\,x}{b}\right )}{{\left (c\,x^2+b\,x\right )}^{4/3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(b*x + c*x^2)^(4/3),x)

[Out]

-(3*x*((c*x)/b + 1)^(4/3)*hypergeom([-1/3, 4/3], 2/3, -(c*x)/b))/(b*x + c*x^2)^(4/3)

________________________________________________________________________________________

sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\left (b x + c x^{2}\right )^{\frac {4}{3}}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(c*x**2+b*x)**(4/3),x)

[Out]

Integral((b*x + c*x**2)**(-4/3), x)

________________________________________________________________________________________